Implement a function to raise a number to an exponent using your language of choice.

Question

Anonymous · Accepted Answer

int raisingTo(int base, unsigned int exponent)
{
    if (exponent == 0)
        return 1;
    else
        return base * raisingTo(base, exponent - 1);
}

Anonymous · Answer

C++:

#include 

double raise(double nm, double ex)
{
    return pow(nm, ex);
}

The question didn't say that you can't use pow() so ... done.

Other than that, you can indeed fiddle with log/exp:

return exp(ex * log(nm));

but that has some limitations (for example, does not work for nm <= 0, whereas pow() does) ... and when you could use log() and exp(), why you couldn't use pow().

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